18k^2-48k-360=0

Solution for 18k^2-48k-360=0 equation:

18k^2-48k-360=0

a = 18; b = -48; c = -360;
Δ = b2-4ac
Δ = -482-4·18·(-360)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-168}{2*18}=\frac{-120}{36}
=-3+1/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+168}{2*18}=\frac{216}{36}
=6
$